leonv/bsc-consolidated
1
0
Fork 0
Code Issues Pull requests Projects Releases Packages Wiki Activity Actions
bsc-consolidated/.vscode/ltex.hiddenFalsePositives.en-US.txt

61 lines
23 KiB
Text
Raw Blame History

This file contains invisible Unicode characters

This file contains invisible Unicode characters that are indistinguishable to humans but may be processed differently by a computer. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.

{"rule":"POSSESSIVE_APOSTROPHE","sentence":"^\\QFurthermore, in mathematical textbooks equality between morphisms is usually taken for granted, i.e. there is some global notion of equality that is clear to everyone.\\E$"}
{"rule":"SENTENCE_WHITESPACE","sentence":"^\\QKleisli').\\E$"}
{"rule":"SENTENCE_WHITESPACE","sentence":"^\\QConstruction.\\E$"}
{"rule":"NO_SPACE_CLOSING_QUOTE","sentence":"^\\Q[inline]Change quotation marks ”\\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q”: Given a Kleisli triple \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, we get a monad \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q where \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is the object mapping of the Kleisli triple together with the functor action \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is the morphism family of the Kleisli triple where naturality is easy to show and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is a natural transformation defined as \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QLet \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q be a setoid morphism, we define \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q point wise: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q where \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is defined corecursively by: \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QThe following conditions hold: There exists a unit morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any DX, satisfying \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q For any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q there exists a unique morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q satisfying: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q There exists a unique morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q satisfying: &&&& &&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q We will make use of the fact that every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is a final coalgebra: [\\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q] This follows by definition of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QWe call a morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q guarded if there exists an \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q such that the following diagram commutes: &&& &&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QIt suffices to show \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, because then follows: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q We prove this by coinduction using: [inline]Change name of morphism &&& &&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Q[inline]Make this more explicit The first step in both equations can be proven by monicity of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and then using \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and the dual diagram for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q which is a direct consequence of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: &&&& &&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q the last step holds generally for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QFirst we need to show naturality of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, i.e. we need to show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q The needed coalgebra is shown in this diagram: &&&& &&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Next we check the strength laws: [\\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q] To show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q we do coinduction using the following coalgebra: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q [\\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q] We don't need coinduction to show \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, but we need a small helper lemma: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q which is a direct consequence of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QFirst we need to show naturality of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, i.e. we need to show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q The coalgebra for coinduction is: &&&& &&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q We write \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q to abbreviate the rather long coalgebra, i.e. in this diagram \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Q&&&&&&& &&&&&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q then follows from this diagram.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QSince \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is a final coalgebra we get the following proof principle: Given two morphisms \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, to show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q it suffices to show that there exists a coalgebra structure \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q such that the following diagrams commute: &&&&&& &&&&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Uniqueness of the coalgebra morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q then gives us that indeed \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QFirst we need to show naturality of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, i.e. we need to show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q The coalgebra for coinduction is: &&&& &&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q We write \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q to abbreviate the used coalgebra, i.e. in this diagram \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QNext we check the strength laws: [\\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q] To show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q we do coinduction using the following coalgebra: &&& &&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q [\\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q] We don't need coinduction to show \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, but we need a small helper lemma: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q which is a direct consequence of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QIt suffices to show \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, because then follows: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q We prove this by coinduction using: &&& &&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Q[inline]Move this remark to the beginning of proof The first step in both equations can be proven by monicity of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and then using \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and the dual diagram for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q which is a direct consequence of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: &&&& &&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QTo show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q it suffices to show that there exists a coalgebra structure \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q such that the following diagrams commute: &&&&&& &&&&&& \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Uniqueness of the coalgebra morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q then results in \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object X for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q the iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q test: \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object X for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q the iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:uniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:folding Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q test: \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object X for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q the iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:uniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:folding Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:diamond Diamond\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object X for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q the iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:uniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:folding Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object A for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q the iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:uniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:folding Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: Note that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q since \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: Note that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q since \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"UPPERCASE_SENTENCE_START","sentence":"^\\Qlaw:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: Note that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q since \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: First, note that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q can equivalently be reformulated as \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q since \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Using \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, we are left to show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"UPPERCASE_SENTENCE_START","sentence":"^\\Qlaw:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q: First, note that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q can equivalently be reformulated as \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q since \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Using \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, we are left to show that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"IF_IS","sentence":"^\\QLet \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q be a setoid morphism, we define \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q point wise: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\Q\\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object A for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q an iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:uniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q law:folding Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\Qlaw:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, and for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q an iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:uniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q implies \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:folding Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"ENGLISH_WORD_REPEAT_RULE","sentence":"^\\QA (unguarded) Elgot Algebra \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q consists of: An object \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, and for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q an iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying the following axioms: law:fixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:uniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q implies \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:folding Folding: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"MORFOLOGIK_RULE_EN_US","sentence":"^\\QGiven a functor \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, a (H-)guarded Elgot algebra consists of: An object \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, a H-algebra structure \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, and for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q an iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, satisfying the following axioms: law:guardedfixpoint Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:guardeduniformity Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q implies \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:guardedcompositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"UPPERCASE_SENTENCE_START","sentence":"^\\Qlaw:compositionality Compositionality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:stutter Stutter: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, law:diamond Diamond: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"MORFOLOGIK_RULE_EN_US","sentence":"^\\QAn Elgot monad consists of A monad \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, for every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q an iteration \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q satisfying: Fixpoint: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, Uniformity: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q implies \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, Naturality: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, Codiagonal: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"IF_IS","sentence":"^\\QLet \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q be a setoid and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q be a setoid function, we define \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q point wise: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QGiven a function \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, the lifted function \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is defined as \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QConsider, \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q where \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is a setoid function that maps every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q to \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"IF_IS","sentence":"^\\QNow, consider the following function \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q which tries running two computations and returns the one that finished first: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QLastly, consider the function \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, which adds a number of \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q constructors in front of a value and is given by \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QConsider another setoid function \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, defined by \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QNext, let us consider functions for counting steps of computations, first regard \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, which returns the number of steps a terminating computation has to take and is defined by \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QConsider \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q defined by \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QFurthermore, consider the setoid function \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q defined by \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Now, by coinduction we can easily follow that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"WHITESPACE_RULE","sentence":"^\\QFriedrich-Alexander-Universität Erlangen-Nürnberg [] Chair for Computer Science 8 Theoretical Computer Science Bachelor Thesis in Computer Science [0.5] Advisor: Sergey Goncharov Erlangen,\\E$"}
{"rule":"MORFOLOGIK_RULE_EN_US","sentence":"^\\Q[agda] linenos=true, breaklines=true, encoding=utf8, fontsize=, frame=lines, autogobble\\E$"}
{"rule":"WHITESPACE_RULE","sentence":"^\\Q[4][]##4\\E$"}
{"rule":"MORFOLOGIK_RULE_EN_US","sentence":"^\\Q[cases] mycase Case .\\E$"}
{"rule":"COMMA_PARENTHESIS_WHITESPACE","sentence":"^\\Q[cases] mycase Case .\\E$"}
{"rule":"IF_IS","sentence":"^\\QLet \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q be a setoid and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q be a setoid morphism, we define \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q point wise: \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QFurthermore, consider the setoid morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q defined by \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q Now, by coinduction we can easily follow that \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q for any \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"IF_IS","sentence":"^\\QConsider, \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q and \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q where \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q is a setoid morphism that maps every \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q to \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q.\\E$"}
{"rule":"IF_IS","sentence":"^\\QConsider another setoid morphism \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q, defined by \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+\\Q if \\E(?:Dummy|Ina|Jimmy-)[0-9]+$"}
{"rule":"DOUBLE_PUNCTUATION","sentence":"^\\QAgda implements a Martin-Löf style dependent type theory with inductive and coinductive types as well as an infinite hierarchy of universes Set_0, Set_1, , where usually Set_0 is abbreviated as Set.\\E$"}
{"rule":"DOUBLE_PUNCTUATION","sentence":"^\\QAgda implements a Martin-Löf style dependent type theory with inductive and coinductive types as well as an infinite hierarchy of universes Set₀, Set₁, , where usually Set₀ is abbreviated as Set.\\E$"}
Reference in a new issue View git blame Copy permalink